110=-16t^2+85t+4

Solution for 110=-16t^2+85t+4 equation:

110=-16t^2+85t+4

We move all terms to the left:

110-(-16t^2+85t+4)=0

We get rid of parentheses

16t^2-85t-4+110=0

We add all the numbers together, and all the variables

16t^2-85t+106=0

a = 16; b = -85; c = +106;
Δ = b2-4ac
Δ = -852-4·16·106
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-21}{2*16}=\frac{64}{32}
=2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+21}{2*16}=\frac{106}{32}
=3+5/16
$